Solve x-3(x-2)leq4quad2x

$$x - 3 ( x - 2 ) \leq 4 \quad 2 x$$

Solve for x

$$x\geq \frac{3}{5}$$

Solution Steps

Use the distributive property to multiply -3 by x-2.

$$x-3x+6\leq 4\times 2x$$

Combine x and -3x to get -2x.

$$-2x+6\leq 4\times 2x$$

Multiply 4 and 2 to get 8.

$$-2x+6\leq 8x$$

Subtract 8x from both sides.

$$-2x+6-8x\leq 0$$

Combine -2x and -8x to get -10x.

$$-10x+6\leq 0$$

Subtract 6 from both sides. Anything subtracted from zero gives its negation.

$$-10x\leq -6$$

Divide both sides by -10. Since -10 is negative, the inequality direction is changed.

$$x\geq \frac{-6}{-10}$$

Reduce the fraction \frac{-6}{-10} to lowest terms by extracting and canceling out -2.

$$x\geq \frac{3}{5}$$