Solve x-3+y=4x

$$x - 3 + y = 4 x$$

Solve for x

$$x=\frac{y-3}{3}$$

Steps for Solving Linear Equation

Subtract 4x from both sides.

$$x-3+y-4x=0$$

Combine x and -4x to get -3x.

$$-3x-3+y=0$$

Add 3 to both sides. Anything plus zero gives itself.

$$-3x+y=3$$

Subtract y from both sides.

$$-3x=3-y$$

Divide both sides by -3.

$$\frac{-3x}{-3}=\frac{3-y}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$x=\frac{3-y}{-3}$$

Divide 3-y by -3.

$$x=\frac{y}{3}-1$$

Solve for y

$$y=3\left(x+1\right)$$

Solution Steps

Subtract x from both sides.

$$-3+y=4x-x$$

Combine 4x and -x to get 3x.

$$-3+y=3x$$

Add 3 to both sides.

$$y=3x+3$$