Solve x-(-3)+(-24)*(-4)+(-16)-(-30)

$$x - ( - 3 ) + ( - 24 ) \cdot ( - 4 ) + ( - 16 ) - ( - 30 )$$

Evaluate

$$x+113$$

Solution Steps

The opposite of -3 is 3.

$$x+3-24\left(-4\right)-16-\left(-30\right)$$

Multiply -24 and -4 to get 96.

$$x+3+96-16-\left(-30\right)$$

Add 3 and 96 to get 99.

$$x+99-16-\left(-30\right)$$

Subtract 16 from 99 to get 83.

$$x+83-\left(-30\right)$$

The opposite of -30 is 30.

$$x+83+30$$

Add 83 and 30 to get 113.

$$x+113$$

Differentiate w.r.t. x

$$1$$

Steps Using Derivative Rule for Sum

The opposite of -3 is 3.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+3-24\left(-4\right)-16-\left(-30\right))$$

Multiply -24 and -4 to get 96.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+3+96-16-\left(-30\right))$$

Add 3 and 96 to get 99.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+99-16-\left(-30\right))$$

Subtract 16 from 99 to get 83.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+83-\left(-30\right))$$

The opposite of -30 is 30.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+83+30)$$

Add 83 and 30 to get 113.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x+113)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$x^{1-1}$$

Subtract 1 from 1.

$$x^{0}$$

For any term t except 0, t^{0}=1.

$$1$$