Solve for x
x=\frac{\sqrt{3}z+y}{2}
Solve for y
y=-\sqrt{3}z+2x
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x-\sqrt{3}z+x=y
Add x to both sides.
2x-\sqrt{3}z=y
Combine x and x to get 2x.
2x=y+\sqrt{3}z
Add \sqrt{3}z to both sides.
2x=\sqrt{3}z+y
The equation is in standard form.
\frac{2x}{2}=\frac{\sqrt{3}z+y}{2}
Divide both sides by 2.
x=\frac{\sqrt{3}z+y}{2}
Dividing by 2 undoes the multiplication by 2.
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