Solve x-sqrt{3}y+2+sqrt{3}=0

$$x - \sqrt { 3 } y + 2 + \sqrt { 3 } = 0$$

Solve for y

$$y=\frac{\sqrt{3}\left(x+\sqrt{3}+2\right)}{3}$$

Steps for Solving Linear Equation

Subtract 2 from both sides. Anything subtracted from zero gives its negation.

$$x-\sqrt{3}y+\sqrt{3}=-2$$

Subtract \sqrt{3} from both sides.

$$x-\sqrt{3}y=-2-\sqrt{3}$$

Subtract x from both sides.

$$-\sqrt{3}y=-2-\sqrt{3}-x$$

The equation is in standard form.

$$\left(-\sqrt{3}\right)y=-x-\sqrt{3}-2$$

Divide both sides by -\sqrt{3}.

$$\frac{\left(-\sqrt{3}\right)y}{-\sqrt{3}}=\frac{-x-\sqrt{3}-2}{-\sqrt{3}}$$

Dividing by -\sqrt{3} undoes the multiplication by -\sqrt{3}.

$$y=\frac{-x-\sqrt{3}-2}{-\sqrt{3}}$$

Divide -2-\sqrt{3}-x by -\sqrt{3}.

$$y=\frac{\sqrt{3}x}{3}+\frac{2\sqrt{3}}{3}+1$$

Solve for x

$$x=\sqrt{3}y-\sqrt{3}-2$$