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\left(x+2\right)x-3=5
Variable x cannot be equal to -2 since division by zero is not defined. Multiply both sides of the equation by x+2.
x^{2}+2x-3=5
Use the distributive property to multiply x+2 by x.
x^{2}+2x-3-5=0
Subtract 5 from both sides.
x^{2}+2x-8=0
Subtract 5 from -3 to get -8.
x=\frac{-2±\sqrt{2^{2}-4\left(-8\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 2 for b, and -8 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-2±\sqrt{4-4\left(-8\right)}}{2}
Square 2.
x=\frac{-2±\sqrt{4+32}}{2}
Multiply -4 times -8.
x=\frac{-2±\sqrt{36}}{2}
Add 4 to 32.
x=\frac{-2±6}{2}
Take the square root of 36.
x=\frac{4}{2}
Now solve the equation x=\frac{-2±6}{2} when ± is plus. Add -2 to 6.
x=2
Divide 4 by 2.
x=-\frac{8}{2}
Now solve the equation x=\frac{-2±6}{2} when ± is minus. Subtract 6 from -2.
x=-4
Divide -8 by 2.
x=2 x=-4
The equation is now solved.
\left(x+2\right)x-3=5
Variable x cannot be equal to -2 since division by zero is not defined. Multiply both sides of the equation by x+2.
x^{2}+2x-3=5
Use the distributive property to multiply x+2 by x.
x^{2}+2x=5+3
Add 3 to both sides.
x^{2}+2x=8
Add 5 and 3 to get 8.
x^{2}+2x+1^{2}=8+1^{2}
Divide 2, the coefficient of the x term, by 2 to get 1. Then add the square of 1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+2x+1=8+1
Square 1.
x^{2}+2x+1=9
Add 8 to 1.
\left(x+1\right)^{2}=9
Factor x^{2}+2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+1\right)^{2}}=\sqrt{9}
Take the square root of both sides of the equation.
x+1=3 x+1=-3
Simplify.
x=2 x=-4
Subtract 1 from both sides of the equation.