Solve for y
y=3\left(x-3\right)
Solve for x
x=\frac{y+9}{3}
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-\frac{1}{3}y=3-x
Subtract x from both sides.
\frac{-\frac{1}{3}y}{-\frac{1}{3}}=\frac{3-x}{-\frac{1}{3}}
Multiply both sides by -3.
y=\frac{3-x}{-\frac{1}{3}}
Dividing by -\frac{1}{3} undoes the multiplication by -\frac{1}{3}.
y=3x-9
Divide 3-x by -\frac{1}{3} by multiplying 3-x by the reciprocal of -\frac{1}{3}.
x=3+\frac{1}{3}y
Add \frac{1}{3}y to both sides.
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Limits
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