Solve x(1-k)+3=k

$$x ( 1 - k ) + 3 = k$$

Solve for k

$$k=\frac{x+3}{x+1}$$

$$x\neq -1$$

Steps for Solving Linear Equation

Use the distributive property to multiply x by 1-k.

$$x-xk+3=k$$

Subtract k from both sides.

$$x-xk+3-k=0$$

Subtract x from both sides. Anything subtracted from zero gives its negation.

$$-xk+3-k=-x$$

Subtract 3 from both sides.

$$-xk-k=-x-3$$

Combine all terms containing k.

$$\left(-x-1\right)k=-x-3$$

Divide both sides by -x-1.

$$\frac{\left(-x-1\right)k}{-x-1}=\frac{-x-3}{-x-1}$$

Dividing by -x-1 undoes the multiplication by -x-1.

$$k=\frac{-x-3}{-x-1}$$

Divide -x-3 by -x-1.

$$k=\frac{x+3}{x+1}$$

Solve for x

$$x=-\frac{3-k}{1-k}$$

$$k\neq 1$$

Steps for Solving Linear Equation

Use the distributive property to multiply x by 1-k.

$$x-xk+3=k$$

Subtract 3 from both sides.

$$x-xk=k-3$$

Combine all terms containing x.

$$\left(1-k\right)x=k-3$$

Divide both sides by 1-k.

$$\frac{\left(1-k\right)x}{1-k}=\frac{k-3}{1-k}$$

Dividing by 1-k undoes the multiplication by 1-k.

$$x=\frac{k-3}{1-k}$$