Solve x(-4^2)-(2div2*1)-4

$$x ( - 4 ^ { 2 } ) - ( 2 \div 2 \times 1 ) - 4$$

Evaluate

$$-16x-5$$

Solution Steps

Divide 2 by 2 to get 1.

$$x\left(-4^{2}\right)-1\times 1-4$$

Calculate 4 to the power of 2 and get 16.

$$x\left(-16\right)-1\times 1-4$$

Multiply 1 and 1 to get 1.

$$x\left(-16\right)-1-4$$

Subtract 4 from -1 to get -5.

$$x\left(-16\right)-5$$

Differentiate w.r.t. x

$$-16$$

Steps Using Derivative Rule for Sum

Divide 2 by 2 to get 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\left(-4^{2}\right)-1\times 1-4)$$

Calculate 4 to the power of 2 and get 16.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\left(-16\right)-1\times 1-4)$$

Multiply 1 and 1 to get 1.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\left(-16\right)-1-4)$$

Subtract 4 from -1 to get -5.

$$\frac{\mathrm{d}}{\mathrm{d}x}(x\left(-16\right)-5)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-16x^{1-1}$$

Subtract 1 from 1.

$$-16x^{0}$$

For any term t except 0, t^{0}=1.

$$-16$$