Solve x*(-1/3)+7div3=7*(x/9+1)

$$x \times ( - \frac { 1 } { 3 } ) + 7 \div 3 = 7 \times ( \frac { x } { 9 } + 1 )$$

Solve for x

$$x = -\frac{21}{5} = -4\frac{1}{5} = -4.2$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 9, the least common multiple of 3,9.

$$9x\left(-\frac{1}{3}\right)+21=63\left(\frac{x}{9}+1\right)$$

Express 9\left(-\frac{1}{3}\right) as a single fraction.

$$\frac{9\left(-1\right)}{3}x+21=63\left(\frac{x}{9}+1\right)$$

Multiply 9 and -1 to get -9.

$$\frac{-9}{3}x+21=63\left(\frac{x}{9}+1\right)$$

Divide -9 by 3 to get -3.

$$-3x+21=63\left(\frac{x}{9}+1\right)$$

Use the distributive property to multiply 63 by \frac{x}{9}+1.

$$-3x+21=63\times \frac{x}{9}+63$$

Cancel out 9, the greatest common factor in 63 and 9.

$$-3x+21=7x+63$$

Subtract 7x from both sides.

$$-3x+21-7x=63$$

Combine -3x and -7x to get -10x.

$$-10x+21=63$$

Subtract 21 from both sides.

$$-10x=63-21$$

Subtract 21 from 63 to get 42.

$$-10x=42$$

Divide both sides by -10.

$$x=\frac{42}{-10}$$

Reduce the fraction \frac{42}{-10} to lowest terms by extracting and canceling out 2.

$$x=-\frac{21}{5}$$