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x\times \frac{4}{3}=-\frac{8}{45}+\frac{2}{5}
Add \frac{2}{5} to both sides.
x\times \frac{4}{3}=-\frac{8}{45}+\frac{18}{45}
Least common multiple of 45 and 5 is 45. Convert -\frac{8}{45} and \frac{2}{5} to fractions with denominator 45.
x\times \frac{4}{3}=\frac{-8+18}{45}
Since -\frac{8}{45} and \frac{18}{45} have the same denominator, add them by adding their numerators.
x\times \frac{4}{3}=\frac{10}{45}
Add -8 and 18 to get 10.
x\times \frac{4}{3}=\frac{2}{9}
Reduce the fraction \frac{10}{45} to lowest terms by extracting and canceling out 5.
x=\frac{2}{9}\times \frac{3}{4}
Multiply both sides by \frac{3}{4}, the reciprocal of \frac{4}{3}.
x=\frac{2\times 3}{9\times 4}
Multiply \frac{2}{9} times \frac{3}{4} by multiplying numerator times numerator and denominator times denominator.
x=\frac{6}{36}
Do the multiplications in the fraction \frac{2\times 3}{9\times 4}.
x=\frac{1}{6}
Reduce the fraction \frac{6}{36} to lowest terms by extracting and canceling out 6.