Solve for x
x=3\sqrt{5}\approx 6.708203932
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x\times 2\sqrt{5}-5=x\sqrt{5}+10
Factor 20=2^{2}\times 5. Rewrite the square root of the product \sqrt{2^{2}\times 5} as the product of square roots \sqrt{2^{2}}\sqrt{5}. Take the square root of 2^{2}.
x\times 2\sqrt{5}-5-x\sqrt{5}=10
Subtract x\sqrt{5} from both sides.
x\sqrt{5}-5=10
Combine x\times 2\sqrt{5} and -x\sqrt{5} to get x\sqrt{5}.
x\sqrt{5}=10+5
Add 5 to both sides.
x\sqrt{5}=15
Add 10 and 5 to get 15.
\sqrt{5}x=15
The equation is in standard form.
\frac{\sqrt{5}x}{\sqrt{5}}=\frac{15}{\sqrt{5}}
Divide both sides by \sqrt{5}.
x=\frac{15}{\sqrt{5}}
Dividing by \sqrt{5} undoes the multiplication by \sqrt{5}.
x=3\sqrt{5}
Divide 15 by \sqrt{5}.
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