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x\leq x+\frac{1}{5}
Divide each term of 5x+1 by 5 to get x+\frac{1}{5}.
x-x\leq \frac{1}{5}
Subtract x from both sides.
0\leq \frac{1}{5}
Combine x and -x to get 0.
x\in \mathrm{R}
This is true for any x.