Solve x*y=(x+4)(y+4)-4

$$x \cdot y = ( x + 4 ) ( y + 4 ) - 4$$

Solve for x

$$x=-y-3$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+4 by y+4.

$$xy=xy+4x+4y+16-4$$

Subtract 4 from 16 to get 12.

$$xy=xy+4x+4y+12$$

Subtract xy from both sides.

$$xy-xy=4x+4y+12$$

Combine xy and -xy to get 0.

$$0=4x+4y+12$$

Swap sides so that all variable terms are on the left hand side.

$$4x+4y+12=0$$

Subtract 4y from both sides. Anything subtracted from zero gives its negation.

$$4x+12=-4y$$

Subtract 12 from both sides.

$$4x=-4y-12$$

Divide both sides by 4.

$$\frac{4x}{4}=\frac{-4y-12}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$x=\frac{-4y-12}{4}$$

Divide -4y-12 by 4.

$$x=-y-3$$

Solve for y

$$y=-x-3$$

Steps for Solving Linear Equation

Use the distributive property to multiply x+4 by y+4.

$$xy=xy+4x+4y+16-4$$

Subtract 4 from 16 to get 12.

$$xy=xy+4x+4y+12$$

Subtract xy from both sides.

$$xy-xy=4x+4y+12$$

Combine xy and -xy to get 0.

$$0=4x+4y+12$$

Swap sides so that all variable terms are on the left hand side.

$$4x+4y+12=0$$

Subtract 4x from both sides. Anything subtracted from zero gives its negation.

$$4y+12=-4x$$

Subtract 12 from both sides.

$$4y=-4x-12$$

Divide both sides by 4.

$$\frac{4y}{4}=\frac{-4x-12}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$y=\frac{-4x-12}{4}$$

Divide -4x-12 by 4.

$$y=-x-3$$