Solve x*(x+4)=x^2+2(3x+5)

$$x \cdot ( x + 4 ) = x ^ { 2 } + 2 ( 3 x + 5 )$$

Solve for x

$$x=-5$$

Steps for Solving Linear Equation

Use the distributive property to multiply x by x+4.

$$x^{2}+4x=x^{2}+2\left(3x+5\right)$$

Use the distributive property to multiply 2 by 3x+5.

$$x^{2}+4x=x^{2}+6x+10$$

Subtract x^{2} from both sides.

$$x^{2}+4x-x^{2}=6x+10$$

Combine x^{2} and -x^{2} to get 0.

$$4x=6x+10$$

Subtract 6x from both sides.

$$4x-6x=10$$

Combine 4x and -6x to get -2x.

$$-2x=10$$

Divide both sides by -2.

$$x=\frac{10}{-2}$$

Divide 10 by -2 to get -5.

$$x=-5$$