Solve x*(sqrt[4]{32})^12=sqrt{2}

$$x \cdot ( \sqrt[ 4 ] { 32 } ) ^ { 12 } = \sqrt { 2 }$$

Solve for x

$$x=\frac{\sqrt{2}}{32768}\approx 0.000043158$$

Steps for Solving Linear Equation

The equation is in standard form.

$$\left(\sqrt[4]{32}\right)^{12}x=\sqrt{2}$$

Divide both sides by \left(\sqrt[4]{32}\right)^{12}.

$$\frac{\left(\sqrt[4]{32}\right)^{12}x}{\left(\sqrt[4]{32}\right)^{12}}=\frac{\sqrt{2}}{\left(\sqrt[4]{32}\right)^{12}}$$

Dividing by \left(\sqrt[4]{32}\right)^{12} undoes the multiplication by \left(\sqrt[4]{32}\right)^{12}.

$$x=\frac{\sqrt{2}}{\left(\sqrt[4]{32}\right)^{12}}$$

Divide \sqrt{2} by \left(\sqrt[4]{32}\right)^{12}.

$$x=\frac{\sqrt{2}}{32768}$$