Solve x*sqrt{2}-2y=4

$$x \cdot \sqrt { 2 } - 2 y = 4$$

Solve for x

$$x=\sqrt{2}\left(y+2\right)$$

Steps for Solving Linear Equation

Add 2y to both sides.

$$x\sqrt{2}=4+2y$$

The equation is in standard form.

$$\sqrt{2}x=2y+4$$

Divide both sides by \sqrt{2}.

$$\frac{\sqrt{2}x}{\sqrt{2}}=\frac{2y+4}{\sqrt{2}}$$

Dividing by \sqrt{2} undoes the multiplication by \sqrt{2}.

$$x=\frac{2y+4}{\sqrt{2}}$$

Divide 4+2y by \sqrt{2}.

$$x=\sqrt{2}\left(y+2\right)$$

Solve for y

$$y=\frac{\sqrt{2}x-4}{2}$$

Steps for Solving Linear Equation

Subtract x\sqrt{2} from both sides.

$$-2y=4-x\sqrt{2}$$

Reorder the terms.

$$-2y=-\sqrt{2}x+4$$

Divide both sides by -2.

$$\frac{-2y}{-2}=\frac{-\sqrt{2}x+4}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$y=\frac{-\sqrt{2}x+4}{-2}$$

Divide -\sqrt{2}x+4 by -2.

$$y=\frac{\sqrt{2}x}{2}-2$$