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\frac{2x^{8}-5x^{4}-10x^{3}}{2}
Factor out \frac{1}{2}.
x^{3}\left(2x^{5}-5x-10\right)
Consider 2x^{8}-5x^{4}-10x^{3}. Factor out x^{3}.
\frac{x^{3}\left(2x^{5}-5x-10\right)}{2}
Rewrite the complete factored expression. Polynomial 2x^{5}-5x-10 is not factored since it does not have any rational roots.
\frac{2\left(x^{8}-5x^{3}\right)}{2}-\frac{5x^{4}}{2}
To add or subtract expressions, expand them to make their denominators the same. Multiply x^{8}-5x^{3} times \frac{2}{2}.
\frac{2\left(x^{8}-5x^{3}\right)-5x^{4}}{2}
Since \frac{2\left(x^{8}-5x^{3}\right)}{2} and \frac{5x^{4}}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{2x^{8}-10x^{3}-5x^{4}}{2}
Do the multiplications in 2\left(x^{8}-5x^{3}\right)-5x^{4}.