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\frac{9x^{6}-6x^{3}+1}{9}
Factor out \frac{1}{9}.
\left(3x^{3}-1\right)^{2}
Consider 9x^{6}-6x^{3}+1. Use the perfect square formula, a^{2}-2ab+b^{2}=\left(a-b\right)^{2}, where a=3x^{3} and b=1.
\frac{\left(3x^{3}-1\right)^{2}}{9}
Rewrite the complete factored expression. Polynomial 3x^{3}-1 is not factored since it does not have any rational roots.