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\left(x^{2}+4t\right)\left(x^{4}-4tx^{2}+16t^{2}\right)
Rewrite x^{6}+64t^{3} as \left(x^{2}\right)^{3}+\left(4t\right)^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).