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\left(x^{2}+5\right)\left(x^{4}-5x^{2}+25\right)
Rewrite x^{6}+125 as \left(x^{2}\right)^{3}+5^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right). The following polynomials are not factored since they do not have any rational roots: x^{2}+5,x^{4}-5x^{2}+25.