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x^{2}y^{2}\left(x^{3}y^{3}-64\right)
Factor out x^{2}y^{2}.
\left(xy-4\right)\left(x^{2}y^{2}+4xy+16\right)
Consider x^{3}y^{3}-64. Rewrite x^{3}y^{3}-64 as \left(xy\right)^{3}-4^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
x^{2}y^{2}\left(xy-4\right)\left(x^{2}y^{2}+4xy+16\right)
Rewrite the complete factored expression.