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t^{2}-t+2=0
Substitute t for x^{2}.
t=\frac{-\left(-1\right)±\sqrt{\left(-1\right)^{2}-4\times 1\times 2}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -1 for b, and 2 for c in the quadratic formula.
t=\frac{1±\sqrt{-7}}{2}
Do the calculations.
t\in \emptyset
Since the square root of a negative number is not defined in the real field, there are no solutions.
x\in \emptyset
Since t=x^{2}, the original equation does not have any solutions.