Solve x^4-b^4

$$x ^ { 4 } - b ^ { 4 }$$

Factor

$$\left(x-b\right)\left(x+b\right)\left(x^{2}+b^{2}\right)$$

Solution Steps

Rewrite x^{4}-b^{4} as \left(x^{2}\right)^{2}-\left(b^{2}\right)^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).

$$\left(x^{2}-b^{2}\right)\left(x^{2}+b^{2}\right)$$

Consider x^{2}-b^{2}. The difference of squares can be factored using the rule: p^{2}-q^{2}=\left(p-q\right)\left(p+q\right).

$$\left(x-b\right)\left(x+b\right)$$

Rewrite the complete factored expression.

$$\left(x-b\right)\left(x+b\right)\left(x^{2}+b^{2}\right)$$

Evaluate

$$x^{4}-b^{4}$$