Solve for a
a=\frac{x^{4}-1}{5x}
x\neq 0
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-5ax-1=-x^{4}
Subtract x^{4} from both sides. Anything subtracted from zero gives its negation.
-5ax=-x^{4}+1
Add 1 to both sides.
\left(-5x\right)a=1-x^{4}
The equation is in standard form.
\frac{\left(-5x\right)a}{-5x}=\frac{1-x^{4}}{-5x}
Divide both sides by -5x.
a=\frac{1-x^{4}}{-5x}
Dividing by -5x undoes the multiplication by -5x.
a=\frac{x^{3}}{5}-\frac{1}{5x}
Divide -x^{4}+1 by -5x.
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