Solve for x
x=2\sqrt{3}\approx 3.464101615
x=-2\sqrt{3}\approx -3.464101615
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t^{2}-24t+144=0
Substitute t for x^{2}.
t=\frac{-\left(-24\right)±\sqrt{\left(-24\right)^{2}-4\times 1\times 144}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -24 for b, and 144 for c in the quadratic formula.
t=\frac{24±0}{2}
Do the calculations.
t=12
Solutions are the same.
x=-2\sqrt{3} x=2\sqrt{3}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for positive t.
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