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Solve for x (complex solution)
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t^{2}-2t+4=0
Substitute t for x^{2}.
t=\frac{-\left(-2\right)±\sqrt{\left(-2\right)^{2}-4\times 1\times 4}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -2 for b, and 4 for c in the quadratic formula.
t=\frac{2±\sqrt{-12}}{2}
Do the calculations.
t=1+\sqrt{3}i t=-\sqrt{3}i+1
Solve the equation t=\frac{2±\sqrt{-12}}{2} when ± is plus and when ± is minus.
x=-\sqrt{2}e^{\frac{\pi i}{6}} x=\sqrt{2}e^{\frac{\pi i}{6}} x=-\sqrt{2}ie^{\frac{\pi i}{3}} x=\sqrt{2}ie^{\frac{\pi i}{3}}
Since x=t^{2}, the solutions are obtained by evaluating x=±\sqrt{t} for each t.