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\left(x-6\right)\left(x^{3}-10x^{2}+26x-20\right)
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 120 and q divides the leading coefficient 1. One such root is 6. Factor the polynomial by dividing it by x-6.
\left(x-2\right)\left(x^{2}-8x+10\right)
Consider x^{3}-10x^{2}+26x-20. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -20 and q divides the leading coefficient 1. One such root is 2. Factor the polynomial by dividing it by x-2.
\left(x-6\right)\left(x-2\right)\left(x^{2}-8x+10\right)
Rewrite the complete factored expression. Polynomial x^{2}-8x+10 is not factored since it does not have any rational roots.