Solve x^4-12x^2-64=

$$x ^ { 4 } - 12 x ^ { 2 } - 64 =$$

Factor

$$\left(x-4\right)\left(x+4\right)\left(x^{2}+4\right)$$

Solution Steps

To factor the expression, solve the equation where it equals to 0.

$$x^{4}-12x^{2}-64=0$$

By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -64 and q divides the leading coefficient 1. List all candidates \frac{p}{q}.

$$±64,±32,±16,±8,±4,±2,±1$$

Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.

$$x=4$$

By Factor theorem, x-k is a factor of the polynomial for each root k. Divide x^{4}-12x^{2}-64 by x-4 to get x^{3}+4x^{2}+4x+16. To factor the result, solve the equation where it equals to 0.

$$x^{3}+4x^{2}+4x+16=0$$

By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 16 and q divides the leading coefficient 1. List all candidates \frac{p}{q}.

$$±16,±8,±4,±2,±1$$

Find one such root by trying out all the integer values, starting from the smallest by absolute value. If no integer roots are found, try out fractions.

$$x=-4$$

By Factor theorem, x-k is a factor of the polynomial for each root k. Divide x^{3}+4x^{2}+4x+16 by x+4 to get x^{2}+4. To factor the result, solve the equation where it equals to 0.

$$x^{2}+4=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 0 for b, and 4 for c in the quadratic formula.

$$x=\frac{0±\sqrt{0^{2}-4\times 1\times 4}}{2}$$

Do the calculations.

$$x=\frac{0±\sqrt{-16}}{2}$$

Polynomial x^{2}+4 is not factored since it does not have any rational roots.

$$x^{2}+4$$

Rewrite the factored expression using the obtained roots.

$$\left(x-4\right)\left(x+4\right)\left(x^{2}+4\right)$$

Evaluate

$$x^{4}-12x^{2}-64$$