Factor
\left(x-2\right)\left(x+1\right)\left(x^{2}+6x+12\right)
Evaluate
\left(x-2\right)\left(x+1\right)\left(x^{2}+6x+12\right)
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\left(x-2\right)\left(x^{3}+7x^{2}+18x+12\right)
By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term -24 and q divides the leading coefficient 1. One such root is 2. Factor the polynomial by dividing it by x-2.
\left(x+1\right)\left(x^{2}+6x+12\right)
Consider x^{3}+7x^{2}+18x+12. By Rational Root Theorem, all rational roots of a polynomial are in the form \frac{p}{q}, where p divides the constant term 12 and q divides the leading coefficient 1. One such root is -1. Factor the polynomial by dividing it by x+1.
\left(x-2\right)\left(x+1\right)\left(x^{2}+6x+12\right)
Rewrite the complete factored expression. Polynomial x^{2}+6x+12 is not factored since it does not have any rational roots.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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