Solve x^4+4x^2-45divx^2+9

$$x ^ { 4 } + 4 x ^ { 2 } - 45 \div x ^ { 2 } + 9$$

Evaluate

$$x^{4}+4x^{2}+9-\frac{45}{x^{2}}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{4}+4x^{2}+9 times \frac{x^{2}}{x^{2}}.

$$\frac{\left(x^{4}+4x^{2}+9\right)x^{2}}{x^{2}}-\frac{45}{x^{2}}$$

Since \frac{\left(x^{4}+4x^{2}+9\right)x^{2}}{x^{2}} and \frac{45}{x^{2}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\left(x^{4}+4x^{2}+9\right)x^{2}-45}{x^{2}}$$

Do the multiplications in \left(x^{4}+4x^{2}+9\right)x^{2}-45.

$$\frac{x^{6}+4x^{4}+9x^{2}-45}{x^{2}}$$

Factor

$$\frac{x^{6}+4x^{4}+9x^{2}-45}{x^{2}}$$