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Solve for x (complex solution)
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x^{4}x^{4}+4=4x^{4}
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x^{4}.
x^{8}+4=4x^{4}
To multiply powers of the same base, add their exponents. Add 4 and 4 to get 8.
x^{8}+4-4x^{4}=0
Subtract 4x^{4} from both sides.
t^{2}-4t+4=0
Substitute t for x^{4}.
t=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 1\times 4}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -4 for b, and 4 for c in the quadratic formula.
t=\frac{4±0}{2}
Do the calculations.
t=2
Solutions are the same.
x=\sqrt[4]{2} x=\sqrt[4]{2}i x=-\sqrt[4]{2} x=-\sqrt[4]{2}i
Since x=t^{4}, the solutions are obtained by solving the equation for each t.
x^{4}x^{4}+4=4x^{4}
Variable x cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by x^{4}.
x^{8}+4=4x^{4}
To multiply powers of the same base, add their exponents. Add 4 and 4 to get 8.
x^{8}+4-4x^{4}=0
Subtract 4x^{4} from both sides.
t^{2}-4t+4=0
Substitute t for x^{4}.
t=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}-4\times 1\times 4}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, -4 for b, and 4 for c in the quadratic formula.
t=\frac{4±0}{2}
Do the calculations.
t=2
Solutions are the same.
x=-\sqrt[4]{2} x=\sqrt[4]{2}
Since x=t^{4}, the solutions are obtained by evaluating x=±\sqrt[4]{t} for positive t.