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\left(xy^{2}+4\right)\left(x^{2}y^{4}-4xy^{2}+16\right)
Rewrite x^{3}y^{6}+64 as \left(xy^{2}\right)^{3}+4^{3}. The sum of cubes can be factored using the rule: a^{3}+b^{3}=\left(a+b\right)\left(a^{2}-ab+b^{2}\right).