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\left(xy-3z\right)\left(x^{2}y^{2}+3xyz+9z^{2}\right)
Rewrite x^{3}y^{3}-27z^{3} as \left(xy\right)^{3}-\left(3z\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).