Solve x^3-y+3-5z=0

$$x ^ { 3 } - y + 3 - 5 z = 0$$

Solve for y

$$y=x^{3}-5z+3$$

Steps for Solving Linear Equation

Subtract x^{3} from both sides. Anything subtracted from zero gives its negation.

$$-y+3-5z=-x^{3}$$

Subtract 3 from both sides.

$$-y-5z=-x^{3}-3$$

Add 5z to both sides.

$$-y=-x^{3}-3+5z$$

The equation is in standard form.

$$-y=-x^{3}+5z-3$$

Divide both sides by -1.

$$\frac{-y}{-1}=\frac{-x^{3}+5z-3}{-1}$$

Dividing by -1 undoes the multiplication by -1.

$$y=\frac{-x^{3}+5z-3}{-1}$$

Divide -x^{3}-3+5z by -1.

$$y=x^{3}-5z+3$$

Solve for x (complex solution)

$$x=e^{\frac{2\pi i}{3}}\sqrt[3]{y+5z-3}$$

$$x=\sqrt[3]{y+5z-3}$$

$$x=e^{\frac{4\pi i}{3}}\sqrt[3]{y+5z-3}$$

Solve for x

$$x=\sqrt[3]{y+5z-3}$$