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\left(x-4c\right)\left(x^{2}+4cx+16c^{2}\right)
Rewrite x^{3}-64c^{3} as x^{3}-\left(4c\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).