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x^{2}\left(x-6\right)-7\left(x-6\right)
Do the grouping x^{3}-6x^{2}-7x+42=\left(x^{3}-6x^{2}\right)+\left(-7x+42\right), and factor out x^{2} in the first and -7 in the second group.
\left(x-6\right)\left(x^{2}-7\right)
Factor out common term x-6 by using distributive property. Polynomial x^{2}-7 is not factored since it does not have any rational roots.