Factor
\left(x-8\right)\left(x^{2}+8x+64\right)
Evaluate
x^{3}-512
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\left(x-8\right)\left(x^{2}+8x+64\right)
Rewrite x^{3}-512 as x^{3}-8^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right). Polynomial x^{2}+8x+64 is not factored since it does not have any rational roots.
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