Solve x^3-5y=7

$$x ^ { 3 } - 5 y = 7$$

Solve for y

$$y=\frac{x^{3}-7}{5}$$

Steps for Solving Linear Equation

Subtract x^{3} from both sides.

$$-5y=7-x^{3}$$

Divide both sides by -5.

$$\frac{-5y}{-5}=\frac{7-x^{3}}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$y=\frac{7-x^{3}}{-5}$$

Divide 7-x^{3} by -5.

$$y=\frac{x^{3}-7}{5}$$

Solve for x (complex solution)

$$x=e^{\frac{2\pi i}{3}}\sqrt[3]{5y+7}$$

$$x=\sqrt[3]{5y+7}$$

$$x=e^{\frac{4\pi i}{3}}\sqrt[3]{5y+7}$$

Solve for x

$$x=\sqrt[3]{5y+7}$$