Solve x^3-5x^2-16x+80divx+20

$$x ^ { 3 } - 5 x ^ { 2 } - 16 x + 80 \div x + 20$$

Evaluate

$$x^{3}-5x^{2}-16x+20+\frac{80}{x}$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{3}-5x^{2}-16x+20 times \frac{x}{x}.

$$\frac{\left(x^{3}-5x^{2}-16x+20\right)x}{x}+\frac{80}{x}$$

Since \frac{\left(x^{3}-5x^{2}-16x+20\right)x}{x} and \frac{80}{x} have the same denominator, add them by adding their numerators.

$$\frac{\left(x^{3}-5x^{2}-16x+20\right)x+80}{x}$$

Do the multiplications in \left(x^{3}-5x^{2}-16x+20\right)x+80.

$$\frac{x^{4}-5x^{3}-16x^{2}+20x+80}{x}$$

Factor

$$\frac{x^{4}-5x^{3}-16x^{2}+20x+80}{x}$$