Solve x^3-4b=0

$$x ^ { 3 } - 4 b = 0$$

Solve for b

$$b=\frac{x^{3}}{4}$$

Steps for Solving Linear Equation

Subtract x^{3} from both sides. Anything subtracted from zero gives its negation.

$$-4b=-x^{3}$$

Divide both sides by -4.

$$\frac{-4b}{-4}=-\frac{x^{3}}{-4}$$

Dividing by -4 undoes the multiplication by -4.

$$b=-\frac{x^{3}}{-4}$$

Divide -x^{3} by -4.

$$b=\frac{x^{3}}{4}$$

Solve for x (complex solution)

$$x=e^{\frac{2\pi i}{3}}\sqrt[3]{4b}$$

$$x=\sqrt[3]{4b}$$

$$x=e^{\frac{4\pi i}{3}}\sqrt[3]{4b}$$

Solve for x

$$x=\sqrt[3]{4b}$$