Factor
\left(x-3y^{2}\right)\left(x^{2}+3xy^{2}+9y^{4}\right)
Evaluate
x^{3}-27y^{6}
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\left(x-3y^{2}\right)\left(x^{2}+3xy^{2}+9y^{4}\right)
Rewrite x^{3}-27y^{6} as x^{3}-\left(3y^{2}\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
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