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x\left(x^{2}-15x+50\right)
Factor out x.
a+b=-15 ab=1\times 50=50
Consider x^{2}-15x+50. Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+50. To find a and b, set up a system to be solved.
-1,-50 -2,-25 -5,-10
Since ab is positive, a and b have the same sign. Since a+b is negative, a and b are both negative. List all such integer pairs that give product 50.
-1-50=-51 -2-25=-27 -5-10=-15
Calculate the sum for each pair.
a=-10 b=-5
The solution is the pair that gives sum -15.
\left(x^{2}-10x\right)+\left(-5x+50\right)
Rewrite x^{2}-15x+50 as \left(x^{2}-10x\right)+\left(-5x+50\right).
x\left(x-10\right)-5\left(x-10\right)
Factor out x in the first and -5 in the second group.
\left(x-10\right)\left(x-5\right)
Factor out common term x-10 by using distributive property.
x\left(x-10\right)\left(x-5\right)
Rewrite the complete factored expression.