Solve x^3-23/4x^2+40/4x

$$x ^ { 3 } - \frac { 23 } { 4 } x ^ { 2 } + \frac { 40 } { 4 } x$$

Factor

$$\frac{x\left(4x^{2}-23x+40\right)}{4}$$

Solution Steps

Factor out \frac{1}{4}.

$$\frac{4x^{3}-23x^{2}+40x}{4}$$

Consider 4x^{3}-23x^{2}+40x. Factor out x.

$$x\left(4x^{2}-23x+40\right)$$

Rewrite the complete factored expression. Polynomial 4x^{2}-23x+40 is not factored since it does not have any rational roots.

$$\frac{x\left(4x^{2}-23x+40\right)}{4}$$

Evaluate

$$x^{3}-\frac{23x^{2}}{4}+10x$$

Solution Steps

Divide 40 by 4 to get 10.

$$x^{3}-\frac{23}{4}x^{2}+10x$$