Solve x^3+x^2+x/3-4

$$x ^ { 3 } + x ^ { 2 } + \frac { x } { 3 } - 4$$

Evaluate

$$x^{3}+x^{2}+\frac{x}{3}-4$$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{3}+x^{2}-4 times \frac{3}{3}.

$$\frac{3\left(x^{3}+x^{2}-4\right)}{3}+\frac{x}{3}$$

Since \frac{3\left(x^{3}+x^{2}-4\right)}{3} and \frac{x}{3} have the same denominator, add them by adding their numerators.

$$\frac{3\left(x^{3}+x^{2}-4\right)+x}{3}$$

Do the multiplications in 3\left(x^{3}+x^{2}-4\right)+x.

$$\frac{3x^{3}+3x^{2}-12+x}{3}$$

Factor

$$\frac{3x^{3}+3x^{2}+x-12}{3}$$

Solution Steps

Factor out \frac{1}{3}. Polynomial 3x^{3}+3x^{2}+x-12 is not factored since it does not have any rational roots.

$$\frac{3x^{3}+3x^{2}+x-12}{3}$$