Solve x^3+2y+1=0

$$x ^ { 3 } + 2 y + 1 = 0$$

Solve for y

$$y=\frac{-x^{3}-1}{2}$$

Steps for Solving Linear Equation

Subtract x^{3} from both sides. Anything subtracted from zero gives its negation.

$$2y+1=-x^{3}$$

Subtract 1 from both sides.

$$2y=-x^{3}-1$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{-x^{3}-1}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{-x^{3}-1}{2}$$

Solve for x (complex solution)

$$x=e^{\frac{2\pi i}{3}}\sqrt[3]{-2y-1}$$

$$x=\sqrt[3]{-2y-1}$$

$$x=e^{\frac{4\pi i}{3}}\sqrt[3]{-2y-1}$$

Solve for x

$$x=\sqrt[3]{-2y-1}$$