Solve x^2-x+3=x^2+x-2

$$x ^ { 2 } - x + 3 = x ^ { 2 } + x - 2$$

Solve for x

$$x = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$x^{2}-x+3-x^{2}=x-2$$

Combine x^{2} and -x^{2} to get 0.

$$-x+3=x-2$$

Subtract x from both sides.

$$-x+3-x=-2$$

Combine -x and -x to get -2x.

$$-2x+3=-2$$

Subtract 3 from both sides.

$$-2x=-2-3$$

Subtract 3 from -2 to get -5.

$$-2x=-5$$

Divide both sides by -2.

$$x=\frac{-5}{-2}$$

Fraction \frac{-5}{-2} can be simplified to \frac{5}{2} by removing the negative sign from both the numerator and the denominator.

$$x=\frac{5}{2}$$