Solve x^2-px+9=0

$$x ^ { 2 } - p x + 9 = 0$$

Solve for p

$$p=x+\frac{9}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-px+9=-x^{2}$$

Subtract 9 from both sides.

$$-px=-x^{2}-9$$

The equation is in standard form.

$$\left(-x\right)p=-x^{2}-9$$

Divide both sides by -x.

$$\frac{\left(-x\right)p}{-x}=\frac{-x^{2}-9}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$p=\frac{-x^{2}-9}{-x}$$

Divide -x^{2}-9 by -x.

$$p=x+\frac{9}{x}$$

Solve for x (complex solution)

$$x=\frac{\sqrt{p^{2}-36}+p}{2}$$

$$x=\frac{-\sqrt{p^{2}-36}+p}{2}$$

Solve for x

$$x=\frac{\sqrt{p^{2}-36}+p}{2}$$

$$x=\frac{-\sqrt{p^{2}-36}+p}{2}\text{, }|p|\geq 6$$