Solve x^2-b=frac{20sqrt{1}}{5}

$$x ^ { 2 } - b = \frac { 20 \sqrt { 1 } } { 5 }$$

Solve for b

$$b=x^{2}-4$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 5.

$$5x^{2}-5b=20\sqrt{1}$$

Calculate the square root of 1 and get 1.

$$5x^{2}-5b=20\times 1$$

Multiply 20 and 1 to get 20.

$$5x^{2}-5b=20$$

Subtract 5x^{2} from both sides.

$$-5b=20-5x^{2}$$

Divide both sides by -5.

$$\frac{-5b}{-5}=\frac{20-5x^{2}}{-5}$$

Dividing by -5 undoes the multiplication by -5.

$$b=\frac{20-5x^{2}}{-5}$$

Divide -5x^{2}+20 by -5.

$$b=x^{2}-4$$

Solve for x (complex solution)

$$x=-\sqrt{b+4}$$

$$x=\sqrt{b+4}$$

Solve for x

$$x=\sqrt{b+4}$$

$$x=-\sqrt{b+4}\text{, }b\geq -4$$