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x^{2}-91x+1960=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-91\right)±\sqrt{\left(-91\right)^{2}-4\times 1960}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, -91 for b, and 1960 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-91\right)±\sqrt{8281-4\times 1960}}{2}
Square -91.
x=\frac{-\left(-91\right)±\sqrt{8281-7840}}{2}
Multiply -4 times 1960.
x=\frac{-\left(-91\right)±\sqrt{441}}{2}
Add 8281 to -7840.
x=\frac{-\left(-91\right)±21}{2}
Take the square root of 441.
x=\frac{91±21}{2}
The opposite of -91 is 91.
x=\frac{112}{2}
Now solve the equation x=\frac{91±21}{2} when ± is plus. Add 91 to 21.
x=56
Divide 112 by 2.
x=\frac{70}{2}
Now solve the equation x=\frac{91±21}{2} when ± is minus. Subtract 21 from 91.
x=35
Divide 70 by 2.
x=56 x=35
The equation is now solved.
x^{2}-91x+1960=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}-91x+1960-1960=-1960
Subtract 1960 from both sides of the equation.
x^{2}-91x=-1960
Subtracting 1960 from itself leaves 0.
x^{2}-91x+\left(-\frac{91}{2}\right)^{2}=-1960+\left(-\frac{91}{2}\right)^{2}
Divide -91, the coefficient of the x term, by 2 to get -\frac{91}{2}. Then add the square of -\frac{91}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-91x+\frac{8281}{4}=-1960+\frac{8281}{4}
Square -\frac{91}{2} by squaring both the numerator and the denominator of the fraction.
x^{2}-91x+\frac{8281}{4}=\frac{441}{4}
Add -1960 to \frac{8281}{4}.
\left(x-\frac{91}{2}\right)^{2}=\frac{441}{4}
Factor x^{2}-91x+\frac{8281}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-\frac{91}{2}\right)^{2}}=\sqrt{\frac{441}{4}}
Take the square root of both sides of the equation.
x-\frac{91}{2}=\frac{21}{2} x-\frac{91}{2}=-\frac{21}{2}
Simplify.
x=56 x=35
Add \frac{91}{2} to both sides of the equation.
x ^ 2 -91x +1960 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 91 rs = 1960
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{91}{2} - u s = \frac{91}{2} + u
Two numbers r and s sum up to 91 exactly when the average of the two numbers is \frac{1}{2}*91 = \frac{91}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{91}{2} - u) (\frac{91}{2} + u) = 1960
To solve for unknown quantity u, substitute these in the product equation rs = 1960
\frac{8281}{4} - u^2 = 1960
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 1960-\frac{8281}{4} = -\frac{441}{4}
Simplify the expression by subtracting \frac{8281}{4} on both sides
u^2 = \frac{441}{4} u = \pm\sqrt{\frac{441}{4}} = \pm \frac{21}{2}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{91}{2} - \frac{21}{2} = 35 s = \frac{91}{2} + \frac{21}{2} = 56
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.